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.duo. // User SearchGreat new UNIAug 28, 2003, 10:32pm
Yayyyyy!!!!!Aug 30, 2003, 1:27pm
Yayyyyy!!!!!Aug 30, 2003, 3:09pm
KOL DEAD?Aug 31, 2003, 10:09am
Lotto?Sep 2, 2003, 6:31pm
Actually... I'd have to agree with him on that point. Age doesn't matter.
I also have to say that I have heard that he is mean though... from other people besides weebo. Never had any first hand experience.  .Duo. (342836) [View Quote] Lotto?Sep 2, 2003, 6:32pm
oh wait I thought that said not, not hot. Ok, that is disturbing, rofl
 .Duo. (342836) [View Quote] Lotto?Sep 2, 2003, 6:33pm
CRAP sorry, I thought that said "not" not "hot." That is disturbing >_<
 .Duo. (342836) [View Quote] Lotto?Sep 5, 2003, 6:44pm
Wow, for once I agree with you completely (:
Especially on the first and last part.  .Duo. (342836) [View Quote] Pain of Quadratics (HTML)Sep 3, 2003, 10:38pm
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=_NextPart_000_0068_01C3725A.352F47E0 ContentType: text/plain; charset="iso88591" ContentTransferEncoding: quotedprintable I can finish my school's entire math curriculum in less than a year. I = just haven't yet, lol. =20 .Duo. (342836) [View Quote] Simplify: [ 2x^2 + x  1 2x^2  5x + 3 ] [6x^2 + x  2 ] [  X  ] / [] [ x^2  1 2x^2  7x + 3 ] [3x^2  7x  6] Now according to my maths teacher... these questions require a 'bit' = of Quadratic solution finding... ha, yeah right... [ 2x^2 + x  1 2x^2  5x + 3 ] [ 6x^2 + x  2 ] [ (2x  1)(x + 1) (2x  3) (x  1) ] [(3x + 2)(2x  1) ] [  X  ] / [  ] [ x^2  1 2x^2  7x + 3 ] [ 3x^2  7x  6 ] [ (x + 1)(x  1) (2x  1)(x  3) ] [ (3x + 2)(x  3) ] There we are... the quadratics, now rip out the top line of each which = is a demo working... =20 [ (2x  1)(x + 1) (2x  3) (x  1) ] [(3x + 2)(2x  1) ] [  X  ] / [  ] [ (x + 1)(x  1) (2x  1)(x  3) ] [ (3x + 2)(x  3) ] Now in the first 2nd level bracket, group the top and bottom row of = terms together using standard multiplication of fraction methods. [ (2x  1)(x + 1)(2x  3)(x  1) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (x + 1)(x  1)(2x  1)(x  3) ] [ (3x + 2)(x  3) ] Now cancel out the like terms in the numerator and denominator. 2x 1 is the first to go... [ (CANCELED)(x + 1)(2x  3)(x  1) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (x + 1)(x  1)(CANCELED)(x  3) ] [ (3x + 2)(x  3) ] Second to be removed is (x + 1)... [ (CANCELED)(2x  3)(x  1) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (CANCELED)(x  1)(x  3) ] [ (3x + 2)(x  3) ] Then x  1 [ (2x  3)(CANCELED) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (CANCELED)(x  3) ] [ (3x + 2)(x  3) ] Not forgeting the divisor, remove 3x + 2 [ (2x  3) ] [ (CANCELED)(2x  1) ] [  ] / [  ] [ (x  3) ] [ (CANCELED)(x  3) ] Leaving us with.... [ (2x  3) ] [(2x  1) ] [  ] / [  ] [ (x  3) ] [ (x  3) ] The we times and flip the division giving us... [ (2x  3) ] [ (x  3) ] [  ] X [  ] [ (x  3) ] [ 2x  1) ] x  3 and x  3 cancel out leaving us with....... [ (2x  3) ] [  ] [ 2x  1) ] Which is, the correct answer >:) This took about half an hour to do = the ruddy question to start with (and even longer to type it out in = here! lol... question 2 of 5 done.. on to #3) And THAT my friends, is why you should think twice about taking A2 = pure mathmatics... (This is A2 P4)  Mark Gahhhhhh!!! =_NextPart_000_0068_01C3725A.352F47E0 ContentType: text/html; charset="iso88591" ContentTransferEncoding: quotedprintable <!DOCTYPE HTML PUBLIC "//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META httpequiv=3DContentType content=3D"text/html; = charset=3Diso88591"> <META content=3D"MSHTML 6.00.2800.1226" name=3DGENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=3D#ffffff> <DIV><FONT face=3DArial size=3D2>I can finish my school's entire math = curriculum in=20 less than a year. I just haven't yet, lol.</FONT></DIV> <DIV><BR> <BR>.Duo. (342836)</DIV> <BLOCKQUOTE dir=3Dltr=20 style=3D"PADDINGRIGHT: 0px; PADDINGLEFT: 5px; MARGINLEFT: 5px; = BORDERLEFT: #000000 2px solid; MARGINRIGHT: 0px"> <DIV>"strike rapier" <<A=20 = href=3D"mailto:strike at Rapiercom.freeserve.co.uk">strike at Rapiercom.freeser= ve.co.uk</A>>=20 [View Quote] ] [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  = ] / [=20  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x  1)(2x  1)(x  = 3) =20 ] [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Now cancel out the like terms in the = numerator=20 and denominator.</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">2x 1 is the first to = go...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x + 1)(2x  3)(x  = 1) =20 ] [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[=20  ] / [ =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x  1)(CANCELED)(x  = 3) =20 ] [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">Second to be removed is (x +=20 1)...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(2x  3)(x  1) = ] =20 [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ =  ] / [=20  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x  1)(x  3) = ] [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Then x  1</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  = 3)(CANCELED) ] =20 [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] / [=20  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x  = 3) ] =20 [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Not forgeting the divisor, remove 3x + = 2</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ] [ = (CANCELED)(2x =20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] / [ = =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x  3) ] = [ =20 (CANCELED)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Leaving us with....</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ] [(2x  = 1)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] / [ =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x  3) ] = [ (x =20 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">The we times and flip the division = giving=20 us...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ] [ (x  = 3)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] X [ =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x  3) ] = [ 2x =20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">x  3 and x  3 cancel out leaving us=20 with.......</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ 2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Which is, the correct answer >:) = This took=20 about half an hour to do the ruddy question to start with = (and even=20 longer to type it out in here! lol... question 2 of 5 done.. on to=20 #3)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">And THAT my friends, is why you should = think=20 twice about taking A2 pure mathmatics... (This is A2 P4)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New"> Mark</FONT></DIV> <DIV><FONT=20 face=3D"Courier = New">Gahhhhhh!!!</FONT></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></= DIV></DIV></DIV></DIV></DIV></DIV></DIV></BLOCKQUOTE></FONT></FONT></BODY= ></HTML> =_NextPart_000_0068_01C3725A.352F47E0 Pain of Quadratics (HTML)Sep 3, 2003, 10:40pm
This is a multipart message in MIME format.
=_NextPart_000_0084_01C3725A.614598C0 ContentType: text/plain; charset="iso88591" ContentTransferEncoding: quotedprintable That's algebra 2? I haven't even taken that and I know how to solve = that... =20 .Duo. (342836) [View Quote] Simplify: [ 2x^2 + x  1 2x^2  5x + 3 ] [6x^2 + x  2 ] [  X  ] / [] [ x^2  1 2x^2  7x + 3 ] [3x^2  7x  6] Now according to my maths teacher... these questions require a 'bit' = of Quadratic solution finding... ha, yeah right... [ 2x^2 + x  1 2x^2  5x + 3 ] [ 6x^2 + x  2 ] [ (2x  1)(x + 1) (2x  3) (x  1) ] [(3x + 2)(2x  1) ] [  X  ] / [  ] [ x^2  1 2x^2  7x + 3 ] [ 3x^2  7x  6 ] [ (x + 1)(x  1) (2x  1)(x  3) ] [ (3x + 2)(x  3) ] There we are... the quadratics, now rip out the top line of each which = is a demo working... =20 [ (2x  1)(x + 1) (2x  3) (x  1) ] [(3x + 2)(2x  1) ] [  X  ] / [  ] [ (x + 1)(x  1) (2x  1)(x  3) ] [ (3x + 2)(x  3) ] Now in the first 2nd level bracket, group the top and bottom row of = terms together using standard multiplication of fraction methods. [ (2x  1)(x + 1)(2x  3)(x  1) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (x + 1)(x  1)(2x  1)(x  3) ] [ (3x + 2)(x  3) ] Now cancel out the like terms in the numerator and denominator. 2x 1 is the first to go... [ (CANCELED)(x + 1)(2x  3)(x  1) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (x + 1)(x  1)(CANCELED)(x  3) ] [ (3x + 2)(x  3) ] Second to be removed is (x + 1)... [ (CANCELED)(2x  3)(x  1) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (CANCELED)(x  1)(x  3) ] [ (3x + 2)(x  3) ] Then x  1 [ (2x  3)(CANCELED) ] [(3x + 2)(2x  1) ] [  ] / [  ] [ (CANCELED)(x  3) ] [ (3x + 2)(x  3) ] Not forgeting the divisor, remove 3x + 2 [ (2x  3) ] [ (CANCELED)(2x  1) ] [  ] / [  ] [ (x  3) ] [ (CANCELED)(x  3) ] Leaving us with.... [ (2x  3) ] [(2x  1) ] [  ] / [  ] [ (x  3) ] [ (x  3) ] The we times and flip the division giving us... [ (2x  3) ] [ (x  3) ] [  ] X [  ] [ (x  3) ] [ 2x  1) ] x  3 and x  3 cancel out leaving us with....... [ (2x  3) ] [  ] [ 2x  1) ] Which is, the correct answer >:) This took about half an hour to do = the ruddy question to start with (and even longer to type it out in = here! lol... question 2 of 5 done.. on to #3) And THAT my friends, is why you should think twice about taking A2 = pure mathmatics... (This is A2 P4)  Mark Gahhhhhh!!! =_NextPart_000_0084_01C3725A.614598C0 ContentType: text/html; charset="iso88591" ContentTransferEncoding: quotedprintable <!DOCTYPE HTML PUBLIC "//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META httpequiv=3DContentType content=3D"text/html; = charset=3Diso88591"> <META content=3D"MSHTML 6.00.2800.1226" name=3DGENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=3D#ffffff> <DIV><FONT face=3DArial size=3D2>That's algebra 2? I haven't even taken = that and I=20 know how to solve that...</FONT></DIV> <DIV><BR> <BR>.Duo. (342836)</DIV> <BLOCKQUOTE dir=3Dltr=20 style=3D"PADDINGRIGHT: 0px; PADDINGLEFT: 5px; MARGINLEFT: 5px; = BORDERLEFT: #000000 2px solid; MARGINRIGHT: 0px"> <DIV>"strike rapier" <<A=20 = href=3D"mailto:strike at Rapiercom.freeserve.co.uk">strike at Rapiercom.freeser= ve.co.uk</A>>=20 [View Quote] ] [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  = ] / [=20  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x  1)(2x  1)(x  = 3) =20 ] [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Now cancel out the like terms in the = numerator=20 and denominator.</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">2x 1 is the first to = go...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x + 1)(2x  3)(x  = 1) =20 ] [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[=20  ] / [ =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x  1)(CANCELED)(x  = 3) =20 ] [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">Second to be removed is (x +=20 1)...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(2x  3)(x  1) = ] =20 [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ =  ] / [=20  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x  1)(x  3) = ] [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Then x  1</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  = 3)(CANCELED) ] =20 [(3x + 2)(2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] / [=20  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x  = 3) ] =20 [ (3x + 2)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Not forgeting the divisor, remove 3x + = 2</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ] [ = (CANCELED)(2x =20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] / [ = =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x  3) ] = [ =20 (CANCELED)(x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Leaving us with....</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ] [(2x  = 1)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] / [ =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x  3) ] = [ (x =20 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">The we times and flip the division = giving=20 us...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ] [ (x  = 3)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ] X [ =20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x  3) ] = [ 2x =20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">x  3 and x  3 cancel out leaving us=20 with.......</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x  3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[  ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ 2x  1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Which is, the correct answer >:) = This took=20 about half an hour to do the ruddy question to start with = (and even=20 longer to type it out in here! lol... question 2 of 5 done.. on to=20 #3)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">And THAT my friends, is why you should = think=20 twice about taking A2 pure mathmatics... (This is A2 P4)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New"> Mark</FONT></DIV> <DIV><FONT=20 face=3D"Courier = New">Gahhhhhh!!!</FONT></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></= DIV></DIV></DIV></DIV></DIV></DIV></DIV></BLOCKQUOTE></FONT></FONT></BODY= ></HTML> =_NextPart_000_0084_01C3725A.614598C0 Pain of Quadratics (HTML)Sep 4, 2003, 7:56pm
lol, guess so. BTW, I'm not clipping my posts just to torture strike >:P
 .Duo. (342836) [View Quote] Sterotype JokeSep 4, 2003, 7:56pm
Squaring the circleSep 4, 2003, 10:30pm
Squaring the circleSep 5, 2003, 6:46pm
Well then, I'll just have to PING you to death.
Nope, don't know how (don't think it can be done either).  .Duo. (342836) [View Quote] Squaring the circleSep 6, 2003, 11:55pm
umm... not really, not if you keep all the verticies (excuse spelling). or
whatever, lol.  .Duo. (342836) [View Quote] Squaring the circleSep 7, 2003, 11:03am
right, which is what I was saying. Also, some people just say it has no
vertices.  .Duo. (342836) [View Quote] Squaring the circleSep 8, 2003, 6:27pm
Squaring the circleSep 8, 2003, 7:03pm
Umm... yeah, but you can't bend the edges of a drawing of a square so it's a
circle. You could do it on a computer though, heh heh heh.  .Duo. (342836) [View Quote] Squaring the circleSep 8, 2003, 7:06pm
Squaring the circleSep 8, 2003, 10:47pm
Squaring the circleSep 9, 2003, 5:19pm
