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.duo. // User SearchGreat new UNIAug 28, 2003, 10:32pm
Yayyyyy!!!!!Aug 30, 2003, 1:27pm
Yayyyyy!!!!!Aug 30, 2003, 3:09pm
KOL DEAD?Aug 31, 2003, 10:09am
Lotto?Sep 2, 2003, 6:31pm
Actually... I'd have to agree with him on that point. Age doesn't matter.
I also have to say that I have heard that he is mean though... from other people besides weebo. Never had any first hand experience. -- -.Duo. (342836) [View Quote] Lotto?Sep 2, 2003, 6:32pm
oh wait I thought that said not, not hot. Ok, that is disturbing, rofl
-- -.Duo. (342836) [View Quote] Lotto?Sep 2, 2003, 6:33pm
CRAP sorry, I thought that said "not" not "hot." That is disturbing >_<
-- -.Duo. (342836) [View Quote] Lotto?Sep 5, 2003, 6:44pm
Wow, for once I agree with you completely (-:
Especially on the first and last part. -- -.Duo. (342836) [View Quote] Pain of Quadratics (HTML)Sep 3, 2003, 10:38pm
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------=_NextPart_000_0068_01C3725A.352F47E0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable I can finish my school's entire math curriculum in less than a year. I = just haven't yet, lol. --=20 -.Duo. (342836) [View Quote] Simplify: [ 2x^2 + x - 1 2x^2 - 5x + 3 ] [6x^2 + x - 2 ] [ ------------ X ------------- ] / [-------------] [ x^2 - 1 2x^2 - 7x + 3 ] [3x^2 - 7x - 6] Now according to my maths teacher... these questions require a 'bit' = of Quadratic solution finding... ha, yeah right... [ 2x^2 + x - 1 2x^2 - 5x + 3 ] [ 6x^2 + x - 2 ] [ (2x - 1)(x + 1) (2x - 3) (x - 1) ] [(3x + 2)(2x - 1) ] [ --------------- X ---------------- ] / [ --------------- ] [ x^2 - 1 2x^2 - 7x + 3 ] [ 3x^2 - 7x - 6 ] [ (x + 1)(x - 1) (2x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] There we are... the quadratics, now rip out the top line of each which = is a demo working... =20 [ (2x - 1)(x + 1) (2x - 3) (x - 1) ] [(3x + 2)(2x - 1) ] [ --------------- X ---------------- ] / [ --------------- ] [ (x + 1)(x - 1) (2x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] Now in the first 2nd level bracket, group the top and bottom row of = terms together using standard multiplication of fraction methods. [ (2x - 1)(x + 1)(2x - 3)(x - 1) ] [(3x + 2)(2x - 1) ] [ ------------------------------- ] / [ --------------- ] [ (x + 1)(x - 1)(2x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] Now cancel out the like terms in the numerator and denominator. 2x -1 is the first to go... [ (CANCELED)(x + 1)(2x - 3)(x - 1) ] [(3x + 2)(2x - 1) ] [ --------------------------------- ] / [ --------------- ] [ (x + 1)(x - 1)(CANCELED)(x - 3) ] [ (3x + 2)(x - 3) ] Second to be removed is (x + 1)... [ (CANCELED)(2x - 3)(x - 1) ] [(3x + 2)(2x - 1) ] [ -------------------------- ] / [ --------------- ] [ (CANCELED)(x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] Then x - 1 [ (2x - 3)(CANCELED) ] [(3x + 2)(2x - 1) ] [ ------------------ ] / [ --------------- ] [ (CANCELED)(x - 3) ] [ (3x + 2)(x - 3) ] Not forgeting the divisor, remove 3x + 2 [ (2x - 3) ] [ (CANCELED)(2x - 1) ] [ -------- ] / [ ------------------ ] [ (x - 3) ] [ (CANCELED)(x - 3) ] Leaving us with.... [ (2x - 3) ] [(2x - 1) ] [ -------- ] / [ ------- ] [ (x - 3) ] [ (x - 3) ] The we times and flip the division giving us... [ (2x - 3) ] [ (x - 3) ] [ -------- ] X [ ------- ] [ (x - 3) ] [ 2x - 1) ] x - 3 and x - 3 cancel out leaving us with....... [ (2x - 3) ] [ -------- ] [ 2x - 1) ] Which is, the correct answer >:) This took about half an hour to do = the ruddy question to start with (and even longer to type it out in = here! lol... question 2 of 5 done.. on to #3) And THAT my friends, is why you should think twice about taking A2 = pure mathmatics... (This is A2 P4) - Mark Gahhhhhh!!! ------=_NextPart_000_0068_01C3725A.352F47E0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META http-equiv=3DContent-Type content=3D"text/html; = charset=3Diso-8859-1"> <META content=3D"MSHTML 6.00.2800.1226" name=3DGENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=3D#ffffff> <DIV><FONT face=3DArial size=3D2>I can finish my school's entire math = curriculum in=20 less than a year. I just haven't yet, lol.</FONT></DIV> <DIV><BR>-- <BR>-.Duo. (342836)</DIV> <BLOCKQUOTE dir=3Dltr=20 style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; = BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px"> <DIV>"strike rapier" <<A=20 = href=3D"mailto:strike at Rapiercom.freeserve.co.uk">strike at Rapiercom.freeser= ve.co.uk</A>>=20 [View Quote] ] [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ ------------------------------- = ] / [=20 --------------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x - 1)(2x - 1)(x - = 3) =20 ] [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Now cancel out the like terms in the = numerator=20 and denominator.</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">2x -1 is the first to = go...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x + 1)(2x - 3)(x - = 1) =20 ] [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[=20 --------------------------------- ] / [ ---------------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x - 1)(CANCELED)(x - = 3) =20 ] [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">Second to be removed is (x +=20 1)...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(2x - 3)(x - 1) = ] =20 [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ = -------------------------- ] / [=20 --------------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x - 1)(x - 3) = ] [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Then x - 1</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - = 3)(CANCELED) ] =20 [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ ------------------ ] / [=20 --------------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x - = 3) ] =20 [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Not forgeting the divisor, remove 3x + = 2</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ] [ = (CANCELED)(2x -=20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ] / [ = ------------------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x - 3) ] = [ =20 (CANCELED)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Leaving us with....</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ] [(2x - = 1)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ] / [ -------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x - 3) ] = [ (x -=20 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">The we times and flip the division = giving=20 us...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ] [ (x - = 3)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ] X [ -------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x - 3) ] = [ 2x -=20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">x - 3 and x - 3 cancel out leaving us=20 with.......</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ 2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Which is, the correct answer >:) = This took=20 about half an hour to do the ruddy question to start with = (and even=20 longer to type it out in here! lol... question 2 of 5 done.. on to=20 #3)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">And THAT my friends, is why you should = think=20 twice about taking A2 pure mathmatics... (This is A2 P4)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">- Mark</FONT></DIV> <DIV><FONT=20 face=3D"Courier = New">Gahhhhhh!!!</FONT></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></= DIV></DIV></DIV></DIV></DIV></DIV></DIV></BLOCKQUOTE></FONT></FONT></BODY= ></HTML> ------=_NextPart_000_0068_01C3725A.352F47E0-- Pain of Quadratics (HTML)Sep 3, 2003, 10:40pm
This is a multi-part message in MIME format.
------=_NextPart_000_0084_01C3725A.614598C0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable That's algebra 2? I haven't even taken that and I know how to solve = that... --=20 -.Duo. (342836) [View Quote] Simplify: [ 2x^2 + x - 1 2x^2 - 5x + 3 ] [6x^2 + x - 2 ] [ ------------ X ------------- ] / [-------------] [ x^2 - 1 2x^2 - 7x + 3 ] [3x^2 - 7x - 6] Now according to my maths teacher... these questions require a 'bit' = of Quadratic solution finding... ha, yeah right... [ 2x^2 + x - 1 2x^2 - 5x + 3 ] [ 6x^2 + x - 2 ] [ (2x - 1)(x + 1) (2x - 3) (x - 1) ] [(3x + 2)(2x - 1) ] [ --------------- X ---------------- ] / [ --------------- ] [ x^2 - 1 2x^2 - 7x + 3 ] [ 3x^2 - 7x - 6 ] [ (x + 1)(x - 1) (2x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] There we are... the quadratics, now rip out the top line of each which = is a demo working... =20 [ (2x - 1)(x + 1) (2x - 3) (x - 1) ] [(3x + 2)(2x - 1) ] [ --------------- X ---------------- ] / [ --------------- ] [ (x + 1)(x - 1) (2x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] Now in the first 2nd level bracket, group the top and bottom row of = terms together using standard multiplication of fraction methods. [ (2x - 1)(x + 1)(2x - 3)(x - 1) ] [(3x + 2)(2x - 1) ] [ ------------------------------- ] / [ --------------- ] [ (x + 1)(x - 1)(2x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] Now cancel out the like terms in the numerator and denominator. 2x -1 is the first to go... [ (CANCELED)(x + 1)(2x - 3)(x - 1) ] [(3x + 2)(2x - 1) ] [ --------------------------------- ] / [ --------------- ] [ (x + 1)(x - 1)(CANCELED)(x - 3) ] [ (3x + 2)(x - 3) ] Second to be removed is (x + 1)... [ (CANCELED)(2x - 3)(x - 1) ] [(3x + 2)(2x - 1) ] [ -------------------------- ] / [ --------------- ] [ (CANCELED)(x - 1)(x - 3) ] [ (3x + 2)(x - 3) ] Then x - 1 [ (2x - 3)(CANCELED) ] [(3x + 2)(2x - 1) ] [ ------------------ ] / [ --------------- ] [ (CANCELED)(x - 3) ] [ (3x + 2)(x - 3) ] Not forgeting the divisor, remove 3x + 2 [ (2x - 3) ] [ (CANCELED)(2x - 1) ] [ -------- ] / [ ------------------ ] [ (x - 3) ] [ (CANCELED)(x - 3) ] Leaving us with.... [ (2x - 3) ] [(2x - 1) ] [ -------- ] / [ ------- ] [ (x - 3) ] [ (x - 3) ] The we times and flip the division giving us... [ (2x - 3) ] [ (x - 3) ] [ -------- ] X [ ------- ] [ (x - 3) ] [ 2x - 1) ] x - 3 and x - 3 cancel out leaving us with....... [ (2x - 3) ] [ -------- ] [ 2x - 1) ] Which is, the correct answer >:) This took about half an hour to do = the ruddy question to start with (and even longer to type it out in = here! lol... question 2 of 5 done.. on to #3) And THAT my friends, is why you should think twice about taking A2 = pure mathmatics... (This is A2 P4) - Mark Gahhhhhh!!! ------=_NextPart_000_0084_01C3725A.614598C0 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META http-equiv=3DContent-Type content=3D"text/html; = charset=3Diso-8859-1"> <META content=3D"MSHTML 6.00.2800.1226" name=3DGENERATOR> <STYLE></STYLE> </HEAD> <BODY bgColor=3D#ffffff> <DIV><FONT face=3DArial size=3D2>That's algebra 2? I haven't even taken = that and I=20 know how to solve that...</FONT></DIV> <DIV><BR>-- <BR>-.Duo. (342836)</DIV> <BLOCKQUOTE dir=3Dltr=20 style=3D"PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; = BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px"> <DIV>"strike rapier" <<A=20 = href=3D"mailto:strike at Rapiercom.freeserve.co.uk">strike at Rapiercom.freeser= ve.co.uk</A>>=20 [View Quote] ] [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ ------------------------------- = ] / [=20 --------------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x - 1)(2x - 1)(x - = 3) =20 ] [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Now cancel out the like terms in the = numerator=20 and denominator.</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">2x -1 is the first to = go...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x + 1)(2x - 3)(x - = 1) =20 ] [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[=20 --------------------------------- ] / [ ---------------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x + 1)(x - 1)(CANCELED)(x - = 3) =20 ] [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">Second to be removed is (x +=20 1)...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(2x - 3)(x - 1) = ] =20 [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ = -------------------------- ] / [=20 --------------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x - 1)(x - 3) = ] [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Then x - 1</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - = 3)(CANCELED) ] =20 [(3x + 2)(2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ ------------------ ] / [=20 --------------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (CANCELED)(x - = 3) ] =20 [ (3x + 2)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV> <DIV><FONT face=3D"Courier New">Not forgeting the divisor, remove 3x + = 2</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ] [ = (CANCELED)(2x -=20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ] / [ = ------------------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x - 3) ] = [ =20 (CANCELED)(x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Leaving us with....</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ] [(2x - = 1)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ] / [ -------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x - 3) ] = [ (x -=20 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">The we times and flip the division = giving=20 us...</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ] [ (x - = 3)=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ] X [ -------=20 ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ (x - 3) ] = [ 2x -=20 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">x - 3 and x - 3 cancel out leaving us=20 with.......</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV> <DIV><FONT face=3D"Courier New">[ (2x - 3) ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ -------- ]</FONT></DIV> <DIV><FONT face=3D"Courier New">[ 2x - 1) ]</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">Which is, the correct answer >:) = This took=20 about half an hour to do the ruddy question to start with = (and even=20 longer to type it out in here! lol... question 2 of 5 done.. on to=20 #3)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">And THAT my friends, is why you should = think=20 twice about taking A2 pure mathmatics... (This is A2 P4)</FONT></DIV> <DIV><FONT face=3D"Courier New"></FONT> </DIV> <DIV><FONT face=3D"Courier New">- Mark</FONT></DIV> <DIV><FONT=20 face=3D"Courier = New">Gahhhhhh!!!</FONT></DIV></DIV></DIV></DIV></DIV></DIV></DIV></DIV></= DIV></DIV></DIV></DIV></DIV></DIV></DIV></BLOCKQUOTE></FONT></FONT></BODY= ></HTML> ------=_NextPart_000_0084_01C3725A.614598C0-- Pain of Quadratics (HTML)Sep 4, 2003, 7:56pm
lol, guess so. BTW, I'm not clipping my posts just to torture strike >:-P
-- -.Duo. (342836) [View Quote] Sterotype JokeSep 4, 2003, 7:56pm
Squaring the circleSep 4, 2003, 10:30pm
Squaring the circleSep 5, 2003, 6:46pm
Well then, I'll just have to PING you to death.
Nope, don't know how (don't think it can be done either). -- -.Duo. (342836) [View Quote] Squaring the circleSep 6, 2003, 11:55pm
umm... not really, not if you keep all the verticies (excuse spelling). or
whatever, lol. -- -.Duo. (342836) [View Quote] Squaring the circleSep 7, 2003, 11:03am
right, which is what I was saying. Also, some people just say it has no
vertices. -- -.Duo. (342836) [View Quote] Squaring the circleSep 8, 2003, 6:27pm
Squaring the circleSep 8, 2003, 7:03pm
Umm... yeah, but you can't bend the edges of a drawing of a square so it's a
circle. You could do it on a computer though, heh heh heh. -- -.Duo. (342836) [View Quote] Squaring the circleSep 8, 2003, 7:06pm
Squaring the circleSep 8, 2003, 10:47pm
Squaring the circleSep 9, 2003, 5:19pm
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